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Proof step 33 from proof nonnullrefs-in (previous step)

r ≠ jvmref ∧ (∃ m. (val ' + vals0)[m] = refval(r) ∧ ¬ # vals0 < m), ¬ is_referencevalue(val) ∨ val .refval = jvmref, r ∈ vals0 .nonnullrefs ↔ r ≠ jvmref ∧ (∃ m. vals0[m] = refval(r) ∧ m < # vals0) ⊦ r ∈ vals0 .nonnullrefs

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 32:
(val ' + vals0)[m] = refval(r), m ≤ # vals0, ¬ is_referencevalue(val) ∨ val .refval = jvmref ⊦ r = jvmref, r ∈ vals0 .nonnullrefs, ∃ m0. vals0[m0] = refval(r) ∧ ¬ # vals0 ≤ m0

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPNAMEDSEQ : nat, , lels, ⊦ ¬ m < n ↔ n ≤ m])]]