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Proof step 34 from proof nonnullrefs-in (previous step)

¬ is_referencevalue(val) ∨ val .refval = jvmref, r ∈ vals0 .nonnullrefs ↔ r ≠ jvmref ∧ (∃ m. vals0[m] = refval(r) ∧ m < # vals0) ⊦ r ∈ vals0 .nonnullrefs ↔ r ≠ jvmref ∧ (∃ m. (val ' + vals0)[m] = refval(r) ∧ ¬ # vals0 < m)

User applied rule case distinction

And obtained the following new goals

Proof step 26:
r ∈ vals0 .nonnullrefs, ¬ is_referencevalue(val) ∨ val .refval = jvmref, r ∈ vals0 .nonnullrefs ↔ r ≠ jvmref ∧ (∃ m. vals0[m] = refval(r) ∧ m < # vals0) ⊦ r ≠ jvmref ∧ (∃ m. (val ' + vals0)[m] = refval(r) ∧ ¬ # vals0 < m)
Proof step 33:
r ≠ jvmref ∧ (∃ m. (val ' + vals0)[m] = refval(r) ∧ ¬ # vals0 < m), ¬ is_referencevalue(val) ∨ val .refval = jvmref, r ∈ vals0 .nonnullrefs ↔ r ≠ jvmref ∧ (∃ m. vals0[m] = refval(r) ∧ m < # vals0) ⊦ r ∈ vals0 .nonnullrefs

Rule argument

[CASEDARG : pos: right 1, ()]

Additional information

[[CONCRETESIMPRULES : ()]]