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Proof step 12 from proof copy-other-weak (previous step)

n1 + m0 < # ar, n1 < # ar1, n1 < n0, m0 + n0 ≤ m, m + n ≤ # ar, n0 ≤ # ar1, n ≤ # ar0 ⊦ (n1 + m0 < m ∨ m + n ≤ n1 + m0 ⊃ ar[n1 + m0];ar0[(n1 + m0) + 0 - m]) = ar[n1 + m0]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 13:
n ≤ # ar0, n0 ≤ # ar1, m + n ≤ # ar, m0 + n0 ≤ m, n1 < n0, n1 < # ar1, n1 + m0 < # ar ⊦ (n1 + m0 < m ∨ m + n ≤ n1 + m0 ⊃ ar[n1 + m0];ar0[n1 + m0 - m]) = ar[n1 + m0]

Rule argument

Additional information

Used simplifier rules: f: ⊦ m < n → n ≠ 0; from specification nat-basic1%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic1%c: ⊦ m + n = n + m; from specification nat-basic2%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2%add-base: ⊦ n + 0 = n; from specification nat-basic2