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Proof step 6 from proof copy-other-weak (previous step)

n1 < # ar1, n1 < n0, m0 + n0 ≤ m, m + n ≤ # ar, n0 ≤ # ar1, n ≤ # ar0 ⊦ copy(ar0, 0, ar, m, n)[n1 + m0] = ar[n1 + m0]

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 7:
⊦ m0 < # ar1 → copy(ar0, n, ar1, n0, m)[m0] = (m0 < n0 ∨ n0 + m ≤ m0 ⊃ ar1[m0];ar0[m0 + n - n0])
Proof step 8:
¬ n1 + m0 < # ar, n1 < # ar1, n1 < n0, m0 + n0 ≤ m, m + n ≤ # ar, n0 ≤ # ar1, n ≤ # ar0 ⊦ copy(ar0, 0, ar, m, n)[n1 + m0] = ar[n1 + m0]
Proof step 12:
n1 + m0 < # ar, n1 < # ar1, n1 < n0, m0 + n0 ≤ m, m + n ≤ # ar, n0 ≤ # ar1, n ≤ # ar0 ⊦ (n1 + m0 < m ∨ m + n ≤ n1 + m0 ⊃ ar[n1 + m0];ar0[(n1 + m0) + 0 - m]) = ar[n1 + m0]

Rule argument

spec: inst: name: at-copy seq: ⊦ m0 < # ar1 → copy(ar0, n, ar1, n0, m)[m0] = (m0 < n0 ∨ n0 + m ≤ m0 ⊃ ar1[m0];ar0[m0 + n - n0]) subst: [m0, m, n0, ar1, n, ar0] → [n1 + m0, n, m, ar, 0, ar0] flags: rewrite, current

Additional information

Used terms: n1 + m0, n, m, ar, 0, ar0