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Proof step 5 from proof copy-other-weak (previous step)

¬ n0 ≤ n1, n1 < # ar1, n ≤ # ar0, n0 ≤ # ar1, m + n ≤ # ar, m0 + n0 ≤ m ⊦ copy(ar0, 0, ar, m, n)[n1 + m0] = (n0 ≤ n1 ⊃ ar1[n1];ar[n1 + m0])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
n1 < # ar1, n1 < n0, m0 + n0 ≤ m, m + n ≤ # ar, n0 ≤ # ar1, n ≤ # ar0 ⊦ copy(ar0, 0, ar, m, n)[n1 + m0] = ar[n1 + m0]

Rule argument

Additional information

Used simplifier rules: f: ⊦ m < n → n ≠ 0; from specification nat-basic1%fle: ⊦ m < n ∧ n ≤ n0 → m < n0; (forward) from specification nat%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic1%lels-01: ⊦ ¬ m ≤ n ↔ n < m; from specification nat