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Proof step 4 from proof copy-other-weak (previous step)

n1 < # ar1, n ≤ # ar0, n0 ≤ # ar1, m + n ≤ # ar, m0 + n0 ≤ m ⊦ (n0 ≤ n1 ⊃ ar1[n1];copy(ar0, 0, ar, m, n)[n1 + m0]) = (n0 ≤ n1 ⊃ ar1[n1];ar[n1 + m0])

User applied rule case distinction

And obtained the following new goals

Proof step 5:
¬ n0 ≤ n1, n1 < # ar1, n ≤ # ar0, n0 ≤ # ar1, m + n ≤ # ar, m0 + n0 ≤ m ⊦ copy(ar0, 0, ar, m, n)[n1 + m0] = (n0 ≤ n1 ⊃ ar1[n1];ar[n1 + m0])

Rule argument

pos: right 1

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