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Proof step 5 from proof idexcept-extract-right (previous step)

⊦ # ar0 = # ar1 ∧ (∀ m. m < # ar0 ∧ m ≠ n → ar0[m] = ar1[m]) ↔ # ar1 = # ar0 ∧ (∀ n0. n0 < # ar1 → ar1[n0] = ar0[n, ar1[n]][n0])

User applied rule case distinction

And obtained the following new goals

Proof step 6:
# ar0 = # ar1 ∧ (∀ m. m < # ar0 ∧ m ≠ n → ar0[m] = ar1[m]) ⊦ # ar1 = # ar0 ∧ (∀ n0. n0 < # ar1 → ar1[n0] = ar0[n, ar1[n]][n0])
Proof step 10:
# ar1 = # ar0 ∧ (∀ n0. n0 < # ar1 → ar1[n0] = ar0[n, ar1[n]][n0]) ⊦ # ar0 = # ar1 ∧ (∀ m. m < # ar0 ∧ m ≠ n → ar0[m] = ar1[m])

Rule argument

pos: right 1

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