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Proof step 6 from proof idexcept-extract-right (previous step)

# ar0 = # ar1 ∧ (∀ m. m < # ar0 ∧ m ≠ n → ar0[m] = ar1[m]) ⊦ # ar1 = # ar0 ∧ (∀ n0. n0 < # ar1 → ar1[n0] = ar0[n, ar1[n]][n0])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
# ar0 = # ar1, n0 < # ar1, ∀ m. m < # ar1 ∧ m ≠ n → ar0[m] = ar1[m] ⊦ # ar1 = 0, ar1[n0] = ar0[n, ar1[n]][n0]

Rule argument

Additional information

Used simplifier rules: lf-01: ⊦ m < n ∧ n = n0 → m < n0; (forward) from specification nat-basic1%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic1