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Proof step 11 from proof rev-rev (previous step)

¬ n0 < # ar, # ar = n0 + n + 1, n < # ar ⊦ rev(ar)[n0] = ar[n], # ar = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 12:
# ar = n0 + n + 1, n < n0, # ar ≤ n0, n < # ar ⊦ # ar = 0, rev(ar)[n0] = ar[n], n0 = 0

Rule argument

Additional information

Used simplifier rules: f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic1%fle: ⊦ m < n ∧ n ≤ n0 → m < n0; (forward) from specification nat%lels: ⊦ ¬ m < n ↔ n ≤ m; from specification nat