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Proof step 12 from proof rev-rev (previous step)

# ar = n0 + n + 1, n < n0, # ar ≤ n0, n < # ar ⊦ # ar = 0, rev(ar)[n0] = ar[n], n0 = 0

User applied rule insert equation

And closed the goal!

Rule argument

pos: left 1 flags: discard

Additional information

Used simplifier rules: oz: ⊦ m + 1 ≠ 0; from specification nat-basic2%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2%c: ⊦ m + n = n + m; from specification nat-basic2%succ-01: ⊦ m + 1 ≤ n ↔ m < n; from specification nat%l-02: ⊦ ¬ m + n < m; from specification nat-basic2