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Proof step 19 from proof subarray-copy (previous step)

¬(n < n3 ∨ n3 + n2 ≤ n), n + m0 < # ar1, m0 + m1 ≤ # ar1, n < m1 ⊦ ar0[n + n0 - n3] = copy(ar0, n0, copy(ar1, m0, mkarray(m1), 0, m1), n3, n2)[n], m1 = 0, # ar1 = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 20:
n3 < m1, n < n3 + n2, n3 ≤ n, n < m1, m0 + m1 ≤ # ar1, n + m0 < # ar1 ⊦ n3 + n2 = 0, ar0[(n - n3) + n0] = copy(ar0, n0, copy(ar1, m0, mkarray(m1), 0, m1), n3, n2)[n], # ar1 = 0, m1 = 0, n2 = 0

Rule argument

Additional information

Used simplifier rules: l-01: ⊦ m < m + n ↔ n ≠ 0; from specification nat-basic2%fle-01: ⊦ m ≤ n ∧ n < n0 → m < n0; (forward) from specification nat%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic1%lels-01: ⊦ ¬ m ≤ n ↔ n < m; from specification nat%c: ⊦ m + n = n + m; from specification nat-basic2%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2%add-01: ⊦ n ≤ m → m + n0 - n = (m - n) + n0; from specification nat%lels: ⊦ ¬ m < n ↔ n ≤ m; from specification nat