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Proof step 20 from proof subarray-copy (previous step)

n3 < m1, n < n3 + n2, n3 ≤ n, n < m1, m0 + m1 ≤ # ar1, n + m0 < # ar1 ⊦ n3 + n2 = 0, ar0[(n - n3) + n0] = copy(ar0, n0, copy(ar1, m0, mkarray(m1), 0, m1), n3, n2)[n], # ar1 = 0, m1 = 0, n2 = 0

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 21:
n = n1 + n3, n3 < m1, n < n3 + n2, n3 ≤ n, n < m1, m0 + m1 ≤ # ar1, n + m0 < # ar1 ⊦ n3 + n2 = 0, ar0[n1 + n0] = copy(ar0, n0, copy(ar1, m0, mkarray(m1), 0, m1), n3, n2)[n], # ar1 = 0, m1 = 0, n2 = 0

Rule argument

spec: nat inst: name: elim-sub seq: n ≤ m ⊦ n0 = m - n ↔ m = n0 + n subst: [m, n, n0] → [n, n3, n1] flags:

Additional information

Used simplifier rules: n ≤ m ⊦ n0 = m - n ↔ m = n0 + n; (elim) Used terms: n, n3, n1