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Proof step 5 from proof cputput-reverse (previous step)

n0 < # ar ⊦ m = n, ar[m, a][n, b][n0] = ar[n, b][m, a][n0], # ar = 0

Heuristic weak cut applied rule cut formula

And obtained the following new goals

Proof step 6:
n0 < # ar ⊦ n0 = n, m = n, ar[m, a][n, b][n0] = ar[n, b][m, a][n0], # ar = 0

Rule argument

fma: n0 = n

Additional information

Used simplifier rules: Size-put: ⊦ # ar[n, a] = # ar;%cgetput: m < # ar ⊦ ar[m, a][m] = a;%Put-other: ⊦ m ≠ n → ar[n, a][m] = ar[m];%Put-same: ⊦ m < # ar → ar[m, a][m] = a;%lels: ⊦ ¬ m < n ↔ n ≤ m; from specification nat%ls-le-simp: ⊦ m < n → (n ≤ m ↔ false); from specification nat Used formulas: n0 = n