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Proof step 6 from proof cputput-reverse (previous step)

n0 < # ar ⊦ n0 = n, m = n, ar[m, a][n, b][n0] = ar[n, b][m, a][n0], # ar = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
n0 < # ar ⊦ # ar = 0, n0 = n, m = n, ar[m, a][n0] = ar[n, b][m, a][n0]

Rule argument

Additional information

Used simplifier rules: Put-other: ⊦ m ≠ n → ar[n, a][m] = ar[m];