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Proof step 3 from proof cons (
previous step
)
⊦ unique_al((a × d) + ax) ↔ ¬ a ∈ ax ∧ unique_al(ax)
User applied rule insert rewrite lemma
And obtained the following new goals
Proof step 4
:
⊦ unique_al((a × d) + ax) ↔ ¬ a ∈ ax ∧ unique_al(ax)
Rule argument
spec: assoclist inst: name: unique-r seq: ⊦ unique_al((a × d) + ax) ↔ ¬ a ∈ ax ∧ unique_al(ax) subst: [ax, d, a] → [ax, d, a] flags: rewrite, current
Additional information
Used terms: ax, d, a