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Proof step 1 from proof not (conclusion)

⊦ ¬ unique_al(ax) → ¬ unique_al(p ' + ax)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
unique_al(p ' + ax) ⊦ ax = [], ¬ ax.first.1 ∈ ax.rest ∧ unique_al(ax.rest)

Rule argument

Additional information

Used simplifier rules: k-unique-r: ⊦ unique_al(ay) ↔ ay = [] ∨ ¬ ay.first.1 ∈ ay.rest ∧ unique_al(ay.rest);