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Proof step 2 from proof not (previous step)

unique_al(p ' + ax) ⊦ ax = [], ¬ ax.first.1 ∈ ax.rest ∧ unique_al(ax.rest)

Heuristic structural induction applied rule structural induction

And closed the goal!

Rule argument

term: p

Additional information

Used simplifier rules: cons: ⊦ unique_al((a × d)' + ax) ↔ ¬ a ∈ ax ∧ unique_al(ax);%k-unique-r: ⊦ unique_al(ay) ↔ ay = [] ∨ ¬ ay.first.1 ∈ ay.rest ∧ unique_al(ay.rest);%pair freely generated by ×;;%a: ⊦ (ax + ax0) + ax1 = ax + ax0 + ax1; from specification list[assoclista]