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Proof step 3 from proof uniquelen (previous step)

unique_al(ay.rest), ∀ a. ¬ a ∈ ay ⊦ ay = [], ay.first.1 ∈ ay.rest

User applied rule all left

And obtained the following new goals

Proof step 4:
unique_al(ay.rest), ¬ ay.first.1 ∈ ay, ∀ a. ¬ a ∈ ay ⊦ ay = [], ay.first.1 ∈ ay.rest

Rule argument

pos: left 2 terms: ay.first.1 abort: F discard: F computed: F

Additional information

Used terms: ay.first.1