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Proof step 4 from proof uniquelen (previous step)

unique_al(ay.rest), ¬ ay.first.1 ∈ ay, ∀ a. ¬ a ∈ ay ⊦ ay = [], ay.first.1 ∈ ay.rest

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
unique_al(ay.rest), ∀ a. ¬ a ∈ ay ⊦ ay = [], ay.first.1 ∈ ay.rest, ay.first.1 ∈ ay

Rule argument

Additional information