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Theorem choice-aux

ok(a), ∀ b. ok(b) → rel(b, elemf(b)) ∧ ok(elemf(b)) ⊦ ∀ n. ∃ nf. nf(0) = a ∧ ok(nf(n)) ∧ (∀ m. m < n → ok(nf(m)) ∧ nf(m + 1) = elemf(nf(m)))

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