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Proof step 2 from proof abs-neg (previous step)

⊦ abs(0 - i) = abs(i)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Rule argument

spec: int-abs inst: name: elim-sub seq: ⊦ i0 = i - j ↔ i = i0 + j subst: [i, j, i0] → [0, i, i0] flags: rewrite, current

Additional information

Used terms: 0, i, i0