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Proof step 4 from proof abs-neg (previous step)

0 = i0 + i ⊦ abs(i0) = abs(i)

Heuristic weak cut applied rule cut formula

And obtained the following new goals

Rule argument

fma: i0 < 0

Additional information

Used simplifier rules: abs-08: ⊦ i < 0 → abs(i) = ~ i;%Minus-def: ⊦ ~ i = 0 - i;%sub-eq: ⊦ i - j = i0 ↔ i = i0 + j;%forward-le-02: ⊦ j < i ∧ i ≤ 0 → j < 0;%abs-16: ⊦ 0 < j → abs(j) = j;%lf-02: ⊦ i < j ∧ j = i0 → i < i0; (forward) from specification int-basic1%ls-02: ⊦ i < i + j ↔ 0 < j; from specification int-basic2%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2%add-c: ⊦ i + j = j + i; from specification int-basic2 Used formulas: i0 < 0