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Proof step 10 from proof abs-sub-01 (previous step)

~2 < i0 ⊦ ~1 = i0, abs(i0) < i0 + 2

Heuristic weak cut applied rule cut formula

And obtained the following new goals

Proof step 11:
i0 < 0, ~2 < i0 ⊦ ~1 = i0, abs(i0) < i0 + 2

Rule argument

fma: i0 < 0

Additional information

Used simplifier rules: Abs-pos: ⊦ ¬ j < 0 → abs(j) = j;%ls-02: ⊦ i < i + j ↔ 0 < j; from specification int-basic2%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2%add-c: ⊦ i + j = j + i; from specification int-basic2 Used formulas: i0 < 0