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Proof step 11 from proof abs-sub-01 (previous step)

i0 < 0, ~2 < i0 ⊦ ~1 = i0, abs(i0) < i0 + 2

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: int-basic1 inst: name: lst-01 seq: ⊦ ¬ i < j → (i ≠ j ↔ j < i) subst: [j, i] → [i0, ~1] flags: rewrite

Additional information

Used simplifier rules: mone-06: ⊦ ~1 < i ↔ 0 ≤ i;%lels-03: ⊦ i < j → (¬ ¬ j ≤ i ↔ false);%minus-one: ⊦ i < 0 → (~2 < i ↔ i = ~1); from specification int-basic1 Used terms: i0, ~1