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Proof step 5 from proof ple-01 (previous step)

i1 + 1 < j, i1 < j → i1 + 1 + i0 < j + j0 ∨ j0 < 1 + i0 ⊦ j0 < i0, (i1 + 1) + i0 < j + j0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: succ-02: ⊦ i < j + 1 ↔ i ≤ j;%le-def: ⊦ i ≤ j ↔ ¬ j < i;%add-c: ⊦ i + j = j + i; from specification int-basic2%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2