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Proof step 6 from proof ple-01 (previous step)

i1 + 1 < j, i1 < j → ¬ i0 < j0 ⊦ j0 < i0, (i1 + 1) + i0 < j + j0

Heuristic cut applied rule cut formula

And obtained the following new goals

Rule argument

fma: i0 < j0

Additional information

Used simplifier rules: lst-02: ⊦ ¬ i < j → (¬ j < i ↔ i = j); from specification int-basic1%ls-add-both: ⊦ i < j → i1 + i < i1 + j; from specification int-basic2%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2%add-c: ⊦ i + j = j + i; from specification int-basic2 Used formulas: i0 < j0