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Proof step 2 from proof forward-pos (previous step)

0 < j, 0 < i, i < j ⊦ 1 ≠ j ∧ ¬ j < 1

User applied rule case distinction

And obtained the following new goals

Proof step 3:
0 < j, 0 < i, i < j ⊦ 1 ≠ j
Proof step 8:
0 < j, 0 < i, i < j ⊦ ¬ j < 1

Rule argument

pos: right 1

Additional information