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Proof step 3 from proof forward-pos (previous step)

0 < j, 0 < i, i < j ⊦ 1 ≠ j

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
0 < i, i < 1 ⊦

Rule argument

Additional information

Used simplifier rules: trans: ⊦ i < j ∧ j < j0 → i < j0;