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Proof step 24 from proof lst-02 (previous step)

i0 = j -1 ∨ i0 < j -1 ∨ j -1 < i0 ⊦ i0 +1 = j, i0 +1 < j, j < i0 +1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 25:
i0 < j -1 ∨ j -1 < i0 ⊦ i0 +1 = j, i0 +1 < j, j < i0 +1

Rule argument

Additional information

Used simplifier rules: pred: ⊦ i = j -1 ↔ i +1 = j;