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Proof step 25 from proof lst-02 (previous step)

i0 < j -1 ∨ j -1 < i0 ⊦ i0 +1 = j, i0 +1 < j, j < i0 +1

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Rule argument

spec: int-basic1 inst: name: elim-pred seq: ⊦ i = j -1 ↔ j = i +1 subst: [j, i] → [j, i] flags: rewrite, current

Additional information

Used terms: j, i