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Theorem add-a
⊦ i + j + i0 = (i + j) + i0
Type: A user defined theorem
Validity: The proof is valid.
Features: simp, localsimp,
Comment:
Used by:
add-c
,
add-in
,
add-less
,
add-pred-01
,
add-succ-01
,
add-succ-02
,
add-zero-rev
,
eq
,
ex-ls-add
,
ex-oddeven
,
ls
,
ls-01
,
ls-02
,
ls-03
,
ls-add-both
,
ls-succ-01
,
ls-succ-02
,
ls-succ-03
,
ls-zero
,
lst
,
lst-01
,
lst-02
,
lst-03
,
lst-04
,
mone-01
,
mone-02
,
mone-03
,
mthree
,
neq
,
neq-01
,
nls
,
not-zero-pos
,
num-between
,
pls
,
pls-01
,
pls-02
,
pls-03
,
pls-04
,
plst
,
plst-01
,
pred
,
rewz
,
succ
,
succ-01
,
ttwo
,
zero
,
zero-01
,
zero-02
,
zero-03
,
zero-04
,
zero-05
,
zero-06
,
zero-07
,
Used by units in proved state:
int-abs
,
int-mult
,
int-pot
,
int-gcd
,
int-div
,
intnat
,
int-square
,
int-pair
,
int-min
,
Proof exists?: Yes
View
the proof
Infos about the proof
Proved?: Yes
Interactions: 0
Proof steps: 7
Used lemmas:
add-pred
,
add-succ
,
add-zero
,
Used spec theorems:
Used simplifier rules:
int-basic1
/
succ-in
int-basic1
/
pred-in