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Proof step 10 from proof ls-01 (previous step)

∀ j, i0. i1 + j < i1 + i0 ↔ j < i0 ⊦ i1 + j < i1 + i0 ↔ j < i0

User applied rule all left

And closed the goal!

Rule argument

pos: left 1 terms: j, i0 abort: F discard: F computed: T

Additional information

Used terms: j, i0