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Proof step 9 from proof ls-01 (previous step)

∀ j, i0. i1 + j < i1 + i0 ↔ j < i0 ⊦ i1 -1 + j < i1 -1 + i0 ↔ j < i0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: add-pred-01: ⊦ i -1 + j = (i + j)-1;%add-a: ⊦ i + j + i0 = (i + j) + i0;%add-c: ⊦ i + j = j + i;%ls-pred-01: ⊦ i -1 < j -1 ↔ i < j; from specification int-basic1