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Proof step 2 from proof div-eq-same-01 (previous step)

⊦ i / j = i ↔ i = 0 ∨ j = 1, j = 0

User applied rule cut formula

And obtained the following new goals

Proof step 3:
⊦ i = 0, i / j = i ↔ i = 0 ∨ j = 1, j = 0

Rule argument

fma: i = 0

Additional information

Used simplifier rules: zero: j ≠ 0 ⊦ 0 / j = 0; Used formulas: i = 0