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Proof step 3 from proof div-eq-same-01 (
previous step
)
⊦ i = 0, i / j = i ↔ i = 0 ∨ j = 1, j = 0
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 4
:
i / j = i ⊦ j = 0, i = 0, j = 1
Rule argument
Additional information
Used simplifier rules: one: ⊦ i / 1 = i;