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Proof step 7 from proof div-eq-zero-01 (previous step)

i < 0 ⊦ 0 = j, i / j = 0 ↔ 0 < abs(j) + i

User applied rule case distinction

And obtained the following new goals

Proof step 8:
i / j = 0, i < 0 ⊦ 0 < abs(j) + i, 0 = j
Proof step 15:
0 < abs(j) + i, i < 0 ⊦ i / j = 0, 0 = j

Rule argument

pos: right 2

Additional information