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Proof step 8 from proof div-eq-zero-01 (previous step)

i / j = 0, i < 0 ⊦ 0 < abs(j) + i, 0 = j

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
i / j = 0, i < 0, abs(j) + i ≤ 0 ⊦ 0 = j

Rule argument

Additional information

Used simplifier rules: zero-gels-01: ⊦ i < 0 ∧ 0 ≤ j → i < j; from specification int-abs%lf-02: ⊦ i < j ∧ j = i0 → i < i0; (forward) from specification int-basic1%forward-le-04: ⊦ j ≤ i ∧ i ≤ 0 → j ≤ 0; (forward) from specification int-abs%lels: ⊦ ¬ i < j ↔ j ≤ i; from specification int-abs