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Proof step 11 from proof div-mult-01 (previous step)

0 ≤ i, i0 < 0 ⊦ j = 0, i0 = 0, (i * i0) / (j * i0) = i / j

User applied rule cut formula

And obtained the following new goals

Proof step 12:
j < 0, 0 ≤ i, i0 < 0 ⊦ j = 0, i0 = 0, (i * i0) / (j * i0) = i / j
Proof step 15:
0 ≤ i, i0 < 0 ⊦ j < 0, j = 0, i0 = 0, (i * i0) / (j * i0) = i / j

Rule argument

fma: j < 0

Additional information

Used formulas: j < 0