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Proof step 12 from proof div-mult-01 (previous step)

j < 0, 0 ≤ i, i0 < 0 ⊦ j = 0, i0 = 0, (i * i0) / (j * i0) = i / j

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 13:
j < 0, i0 < 0, 0 ≤ i ⊦ (i * i0) / (j * i0) = i / j, i0 = 0, j = 0

Rule argument

Additional information

Used simplifier rules: zero-gels-01: ⊦ i < 0 ∧ 0 ≤ j → i < j; from specification int-abs%forward-le-02: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward) from specification int-abs%forward-lsle: ⊦ i < j ∧ j ≤ j0 → i < j0; (forward) from specification int-abs