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Proof step 18 from proof div-mult-01 (previous step)

⊦ i0 < 0, (i * i0) / (j * i0) = i / j, i0 = 0, j = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 19:
0 < i0 ⊦ j = 0, (i * i0) / (j * i0) = i / j

Rule argument

Additional information

Used simplifier rules: forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs%ls-01: ⊦ i < j → ¬ j < i; from specification int-basic1%lst-01: ⊦ ¬ i < j → (i ≠ j ↔ j < i); from specification int-basic1