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Proof step 19 from proof div-mult-01 (previous step)

0 < i0 ⊦ j = 0, (i * i0) / (j * i0) = i / j

User applied rule cut formula

And obtained the following new goals

Proof step 20:
i < 0, 0 < i0 ⊦ j = 0, (i * i0) / (j * i0) = i / j
Proof step 28:
0 < i0 ⊦ i < 0, j = 0, (i * i0) / (j * i0) = i / j

Rule argument

fma: i < 0

Additional information

Used formulas: i < 0