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Proof step 2 from proof div-same (previous step)

⊦ i / i = 1, i = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
0 < j, j ≤ i ⊦ i / j = (i - j) / j + 1
Proof step 4:
¬(0 < i ∧ i ≤ i) ⊦ i / i = 1, i = 0

Rule argument

spec: int-div inst: name: div-rec seq: 0 < j, j ≤ i ⊦ i / j = (i - j) / j + 1 subst: [j, i] → [i, i] flags: rewrite, current

Additional information

Used simplifier rules: zero: j ≠ 0 ⊦ 0 / j = 0;%sub-sub-03: ⊦ i - i = 0; from specification int-abs%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2%add-c: ⊦ i + j = j + i; from specification int-basic2 Used terms: i, i