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Proof step 4 from proof div-same (previous step)

¬(0 < i ∧ i ≤ i) ⊦ i / i = 1, i = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
i < 0 ⊦ i / i = 1

Rule argument

Additional information

Used simplifier rules: forward-le-02: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward) from specification int-abs%ls-01: ⊦ i < j → ¬ j < i; from specification int-basic1%lst-01: ⊦ ¬ i < j → (i ≠ j ↔ j < i); from specification int-basic1%ler: ⊦ i ≤ i; from specification int-abs