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Proof step 10 from proof div-zero-02 (previous step)

i / ~ j = 0, 0 ≤ i, i + j < 0, j < 0 ⊦ i / j = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 11:
⊦ j ≠ 0 → i / ~ j = ~(i / j)

Rule argument

spec: inst: name: Div-right seq: ⊦ j ≠ 0 → i / ~ j = ~(i / j) subst: [j, i] → [j, i] flags: rewrite, current

Additional information

Used simplifier rules: neg-10: ⊦ ~ i = 0 ↔ i = 0; from specification int-abs Used terms: j, i