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Proof step 9 from proof div-zero-02 (previous step)

i / ~ j = 0, i + j < 0, j < 0, 0 ≤ i ⊦ i / j = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 10:
i / ~ j = 0, 0 ≤ i, i + j < 0, j < 0 ⊦ i / j = 0

Rule argument

Additional information

Used simplifier rules: zero-gels-01: ⊦ i < 0 ∧ 0 ≤ j → i < j; from specification int-abs%lf-02: ⊦ i < j ∧ j = i0 → i < i0; (forward) from specification int-basic1