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Proof step 1 from proof mod-div-zero (conclusion)

⊦ j ≠ 0 → (i % j) / j = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
abs(j) ≤ abs(i % j) ⊦ j = 0

Rule argument

Additional information

Used simplifier rules: div-eq-zero-01: ⊦ 0 ≠ j → (i / j = 0 ↔ abs(i) < abs(j));%lels: ⊦ ¬ i < j ↔ j ≤ i; from specification int-abs