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Proof step 2 from proof mod-div-zero (previous step)

abs(j) ≤ abs(i % j) ⊦ j = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ j ≠ 0 → abs(i % j) = abs(i) % abs(j)
Proof step 4:
j ≠ 0, abs(j) ≤ abs(i) % abs(j) ⊦ j = 0

Rule argument

spec: int-div inst: name: abs-shift seq: ⊦ j ≠ 0 → abs(i % j) = abs(i) % abs(j) subst: [j, i] → [j, i] flags: rewrite, current

Additional information

Used terms: j, i