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Proof step 19 from proof mod-ls-same-02 (previous step)

i < i % j, 0 ≤ i, 0 < i % j ⊦ j = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 20:
⊦ j ≤ i0 ∧ 0 < j → ¬ i0 < i % j
Proof step 21:
¬(j ≤ i ∧ 0 < j), i < i % j, 0 ≤ i, 0 < i % j ⊦ j = 0

Rule argument

spec: int-div inst: name: mod-nls-01 seq: ⊦ j ≤ i0 ∧ 0 < j → ¬ i0 < i % j subst: [j, i, i0] → [j, i, i] flags: rewrite, current

Additional information

Used terms: j, i, i