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Proof step 21 from proof mod-ls-same-02 (
previous step
)
¬(j ≤ i ∧ 0 < j), i < i % j, 0 ≤ i, 0 < i % j ⊦ j = 0
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 22
:
i < i % j, 0 ≤ i, 0 < i % j ⊦ j = 0, j ≤ i ∧ 0 < j
Rule argument
Additional information