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Proof step 3 from proof nls-mult-div (previous step)

i = 0, i < (i * i1) / j, i1 < j, 0 ≤ i, 0 < (i * i1) / j, 0 < j ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
0 < j, i1 < j, 0 < 0 / j ⊦

Rule argument

Additional information

Used simplifier rules: commutativity: ⊦ i * j = j * i; from specification int-mult%associativity: ⊦ i * j * j0 = (i * j) * j0; from specification int-mult%Mult-zero: ⊦ i * 0 = 0; from specification int-mult